Răspuns :
1.
a.
CH3-CH-CH2-CH3
CH3
b.
CH3
CH3-C-CH2-CH3
CH3
c. CH2-CH3
CH3-CH--CH--CH--CH2-CH3
CH3 CH3 CH3
d.
CH3
CH3-CH--C--CH--CH--CH2--CH3
CH3 CH3 CH3
2.
C8H18
CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH3
CH3-CH-CH2-CH2-CH2-CH2-CH3
CH3
CH3-CH2-CH-CH2-CH2-CH2-CH3
CH3
CH3-CH2-CH2-CH-CH2-CH2-CH3
CH3
3.
a.
CH4 + 4Cl2 --lumina--> CCl4 + 4HCl
b.
CH3-CH2-CH2-CH3 <=(AlCl3/50-100oC)=> CH3-CH-CH3
CH3
c.
CH3-CH2-CH3 --(>650oC)--> CH2=CH-CH3 + H2
d.
C4H10 + 13/2O2 --> 4CO2 + 5H2O
4.
hidrocarbura = alcan => CnH2n+2
d.aer = 1,038 , miu.aer = 28,9 g/mol
d.aer = miu.hidroc./miu.aer
=> miu.hidroc. = d.aer x miu.aer = 1,038x28,9 = 30 g/mol
=> 14n+2 = 30 => n = 2
=> C2H6
5.
notam hidroc. = CaHb
d.azot = 2 , miu.N2 = 28 g/mol
d.N2 = miu.hidroc./miu.N2
=> miu.hidroc. = d.N2 x miu.N2 = 2x28 = 56 g/mol
din CO2 ----> C, M.CO2 = 44 g/mol
44g CO2 .................. 12g C
17,6g ......................... m = 4,8g C
5,6g hidroc. - 4,8g = 0,8 g H
=>
5,6g hidroc. ........... 4,8g C ............ 0,8g H
56g ........................ 12a g C ............. b g H
=> a = 4 , b = 8
=> hidroc. = C4H8