Răspuns :

Răspuns:

c)

[tex] \sqrt{6} \times \sqrt{5} - \sqrt{2} \times \sqrt{15} = \\ \sqrt{6 \times 5} - \sqrt{2 \times 15} = \\ \sqrt{30} - \sqrt{30} = 0[/tex]

d)

[tex]3 \sqrt{2} \times \sqrt{2} + \sqrt{2} \times \sqrt{18} = \\ 3 \times \sqrt{4} + \sqrt{36} = \\ 3 \times 2 + 6 = \\ 6 + 6 = 12[/tex]

e)

[tex] \sqrt{3} \times 5 \sqrt{5} - \sqrt{5} \times 3 \sqrt{3} = \\ 5 \sqrt{15} - 3 \sqrt{15} = \\ 2 \sqrt{15} [/tex]

f)

[tex]2 \sqrt{3} + ( - 4 \sqrt{3} ) \times 3 = \\ 2 \sqrt{3 } - 12 \sqrt{3} = - 10 \sqrt{3} [/tex]

Răspuns:

Explicație pas cu pas:

[tex]c) \sqrt{6} * \sqrt{5} - \sqrt{2} * \sqrt{15} =\\= \sqrt{30} - \sqrt{30} =\\= 0[/tex]

[tex]e) \sqrt{3} * 5\sqrt{5} - \sqrt{5} * 3\sqrt{3} =\\= 5\sqrt{15} - 3\sqrt{15} =\\= 2\sqrt{15}[/tex]

[tex]e) \sqrt{3} * 5\sqrt{5} - \sqrt{5} * 3\sqrt{3} =\\= 5\sqrt{15} - 3\sqrt{15} =\\= 2\sqrt{15}[/tex]

[tex]f) 2\sqrt{3} + (-4\sqrt{3} ) * 3\\=2\sqrt{3} + (-12\sqrt{3} ) =\\= 2\sqrt{3} - 12\sqrt{3} =\\= - 10\sqrt{3}[/tex]