Incepem prin a calcula cele doua nr:
a=✓3*(1/✓3+1)= ✓3/✓3+✓3= ✓3+1, ✓3+1<✓9, de unde a<3
b=✓3*(1-1/✓3)= ✓3-✓3/✓3=✓3-1
Mg=✓(a*b)=✓((✓3+1)*(✓3-1))= ✓(9^2-1^2)= ✓80= 4✓5
