Răspuns:
[tex] \sqrt{2} ( \sqrt{6} - 2 \sqrt{10} ) = \sqrt{12} - 2 \sqrt{20} = 2 \sqrt{3} - 4 \sqrt{5} [/tex]
[tex]3( \sqrt{20} + \sqrt{3} ) - \sqrt{3} \times ( \sqrt{5} + 3) = 3(2 \sqrt{5} + 3) - \sqrt{15} - 3 \sqrt{3} = 6 \sqrt{5} + 9 - \sqrt{15} - 3 \sqrt{3} [/tex]
[tex]( \sqrt{18} + \sqrt{12} ) \times 3 \sqrt{2} - \sqrt{216} = (3 \sqrt{2} + 2 \sqrt{3} ) \times 3 \sqrt{2} - 6 \sqrt{6} = 18 + 6 \sqrt{6} - 6 \sqrt{6} = 18[/tex]
