Răspuns :
Răspuns:
1 intreg si 1/2=(1·2+1)/2=3/2
=(⁴⁾13/2-²⁾11/4-15/8)·2/3=52/8-22/8-15/8·2/3=15/8·2/3=30/24=5/4=1,25
1,25 rotunjit 1
__________
dam factor comun3⁴⁰
=√[3⁴⁰(5·3²-2·3-3)]=√[3⁴⁰(45-6-3)]=√(3⁴⁰·36)=6√3⁴⁰=6·3²⁰=2·3·3²=2·3²¹
Răspuns:
1 intreg si 1/2=(1·2+1)/2=3/2
=(⁴⁾13/2-²⁾11/4-15/8)·2/3=52/8-22/8-15/8·2/3=15/8·2/3=30/24=5/4=1,25
1,25 rotunjit 1
__________
dam factor comun3⁴⁰
=√[3⁴⁰(5·3²-2·3-3)]=√[3⁴⁰(45-6-3)]=√(3⁴⁰·36)=6√3⁴⁰=6·3²⁰=2·3·3²=2·3²¹