Răspuns:
Explicație:
1.
ms= 600
c1=30%
md2=20g
cf
md1= c1.ms : 100
md1= 30 . 600 : 100=180g
-se afla md total
md t= 180 + 20=200 g
- ms este aceeasi
cf = mdf .100 : ms
c f= 200 .100: 600=33,3 %
2.
ms=500g
c=20%
md adaugat=30g
c f
md= c. ms : 100
md= 20 .500 : 100= 100g
mdtotal= 100 + 30= 130g
c f= 130 .100 : 500=26%
3.
ms1=400g
c1=30%
ms2=200g
c2=10%
mapa adaugata= 400 g
c f
md1= c1 . ms1 : 100
md1=30 . 400 : 100=120g
md2= 10 . 200 : 100= 20g
md f= 120 + 20= 140 g
ms f= 400 + 200 + 400 = 1000g
c f= md f .100 : ms f
c f= 140 .100 : 1000 = 14 %
4.
ms1=1200g
c1=10%
c2= 20%
mapa evaporata
c1= md .100 : ms1
md= c1 . ms1 : 100
md= 10 . 1200 : 100=120g
c2= md .100 : ms2
ms2= md.100 : c2
ms2= 120. 100 : 20=600g
m apa evap.= ms1 - ms2
= 1200 - 600= 600 g
sau :se calculeaza m1 apa din prima sol.
se calc. m2apa din a doua sol.
mapa evap. = m1apa - m2 apa
