Răspuns:
k)(2×3)^2+2^2·2^5·2^6:(2^3)^4·2^0+3^3·3^4·3^5:(3^5)^2=
6^2+2^7·2^6:2^12·1+3^7·3^5:3^10=
36+2^13:2^12·1+3^12:3^10=
36+2·1+3^2=
36+2+9=
38+9=47
sper că te-am ajutat!
