Răspuns:
[tex]( {2}^{2} ) ^{3} \div {4}^{3} + ({3}^{2}) ^{2} \div ( {2}^{6} - {6}^{2} - {36}^{0}) = \\ {2}^{2 \times 3} \div ( {2}^{2} ) {}^{3} + {3}^{2 \times 2} \div (64 - 36 - 1) = \\ {2}^{6} \div {2}^{2 \times 3} + {3}^{4} \div (28 - 1) = \\ {2}^{6} \div {2}^{6} + {3}^{4} \div 27 = \\ {2}^{6-6} + {3}^{4} \div {3}^{3} = \\ {2}^{0} + {3}^{4 - 3} = \\ 1 + 3 = 4[/tex]
sper că te-am ajutat!
