Răspuns:
8
vo=0,0314m/s=31,4mm/s
T=1s
----------------------------
f=1/T=1/1=1 hertz
ω=2πf=2π·1=2π
v=ωA
314=2πA
A=31,4/2π=31,4/2*3,14=10/2=5mm
y=5sin(2πt)
9.y1=1
v1=2cm/s
y2=3cm
v2=1 cm/s
---------------------------
y1=Asin(ωt+Ф) =1 =>y1=Asinx =1 unde x=ωt+Ф
v1=ωAcos(ωt+Ф)=2 => v1=ωAcosx x=ωt+Ф
y1/v1=Asinx/ωAcosx=1/2 =>
1/ωtgx=1/2=> ωtgx=2
tgx=2/ω rel1
y2=A(sinωt+Ф)= Asinx=3
v2=ωAcox=1
y2/v2=Asinx/ωAcosx =>
tgx/ω=3=>
tgx=3ω rel 2
Egalam relatia 1 si 2
2/ω=3ω
ω²=2/3=0,(6)
v1=ωA
2=2/3A
A=3cm
Explicație:
