Răspuns: 2⁵⁸
Explicație pas cu pas:
Salutare !
[tex]\bf (32^{12}:4+3\cdot 64^{10}):13=[/tex]
[tex]\bf [(2^{5})^{12}:2^{2}+3\cdot (2^{6})^{10}]:13=[/tex]
[tex]\bf (2^{5\cdot 12}:2^{2}+3\cdot 2^{6\cdot 10}):13=[/tex]
[tex]\bf (2^{60}:2^{2}+3\cdot 2^{60}):13=[/tex]
[tex]\bf (2^{60-2}+3\cdot 2^{60}):13=[/tex]
[tex]\bf (2^{58}+3\cdot 2^{60}):13=[/tex]
[tex]\bf 2^{58}\cdot(2^{58-58}+3\cdot 2^{60-58}):13=[/tex]
[tex]\bf 2^{58}\cdot(2^{0}+3\cdot 2^{2}):13=[/tex]
[tex]\bf 2^{58}\cdot(1+3\cdot 4):13=[/tex]
[tex]\bf 2^{58}\cdot 13 : 13 =\boxed{\bf 2^{58}}[/tex]
Cateva formule pentru puteri
a⁰ = 1 sau 1 = a⁰
(aⁿ)ᵇ = aⁿ ˣ ᵇ sau aⁿ ˣ ᵇ = (aⁿ)ᵇ
aⁿ · aᵇ = (a · a)ⁿ ⁺ ᵇ sau (a · a)ⁿ ⁺ ᵇ = aⁿ · aᵇ
aⁿ : aᵇ = (a : a)ⁿ ⁻ ᵇ sau (a : a)ⁿ ⁻ ᵇ = aⁿ : aᵇ
aⁿ · bⁿ = (a · b)ⁿ sau (a · b)ⁿ = aⁿ · bⁿ
aⁿ : bⁿ = (a : b)ⁿ sau (a : b)ⁿ = aⁿ : bⁿ
==pav38==
