Răspuns:
Explicație pas cu pas:
[tex]( \sqrt{150} - 3 \sqrt{10} ) \div \sqrt{2} + ( \sqrt{45} - 5) - \sqrt{75} = \frac{5 \sqrt{6} - 3 \sqrt{10} }{ \sqrt{2} } + 3 \sqrt{5} - 5 - 5 \sqrt{3} = \frac{5 \sqrt{12} - 3 \sqrt{20} }{2} + 3 \sqrt{5} - 5 - 5 \sqrt{3} = 5 \sqrt{3} - 3 \sqrt{5} + 3 \sqrt{5} - 5 - 5 \sqrt{3} = - 5[/tex]
[tex]( \sqrt{54} - \sqrt{24} ) \div \sqrt{3} - ( \sqrt{160} - \sqrt{40} ) \div \sqrt{5} = (3 \sqrt{6} - 2 \sqrt{6} ) \div \sqrt{3} - (4 \sqrt{10} - 2 \sqrt{10} ) \div \sqrt{5} = \sqrt{6} \div \sqrt{3} - 2 \sqrt{10} \div \sqrt{5} = \sqrt{2} - 2 \sqrt{2} = - \sqrt{2} [/tex]
