Răspuns:
a)f(x)= -2x+3
y=-2x+3
y-3=-2x
x=(y-3)/(-2)
f(y)= y/(-2)+3/2
SE trece la variabila x
f⁻⁻¹(x)=-x/2+3/2
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b) f(x)=x/2-1
y=x/2-1
x/2=y+1
x=2y+2
f(y)=2y+2)
f⁻¹(x)=2x+2
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c)f(x)=3x-5
y=3x-5
y+5=3x
x=(y+5)/3
f(y)=(y+5)/3
f⁻¹(x)=(x+5)/3
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d) f(x)= -x/4-2
y= -x/4-2
y+2= -x/4
x=-4y-8
f⁻¹(x)= -4x-8
--------------------------grafic
f⁻¹(x)=-x/2+3/2
f⁻¹(x)=0
-x/2+3=0
-x/2= -3
x=6 B(6,0)
f⁻¹(0)=-0/2+3=3
C(0,3) Gf⁻¹= BC
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f⁻¹(x)=2x+2
f⁻¹(x)=0
2x+2=0
2x= -2
x= -1
D(-1,0)
f⁻⁻¹(0)=2
E(0,2)\
Gf⁻⁻¹=¹DE
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c.f⁻¹(x)=(x+5)/3
f⁻⁻¹(x)=(x+5)/3=0
x= -5) F(-5,0)
f⁻¹(0)=5/3 G(0,5/3)
Gf⁻¹=(FG)
--------------------------
d)f⁻¹(x)= -4x-8
f⁻¹(x)=0
-4x-8=0
-4x=8
x=2
H(2,0)
f⁻¹(0)= -8
I(0,-8)
ATasez imediat si graficele
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