Răspuns :

Răspuns:

[tex] {3}^{104} \div {9}^{51} = \\ {3}^{104} \div ( {3}^{2} ) {}^{51} = \\ {3}^{104} \div {3}^{102} = {3}^{2} = 9 \\ \\ {9}^{3} \times {27}^{2} \div {81}^{3} = \\ ( {3}^{2} ) {}^{3} \times ({3}^{3} ) {}^{2} \div ({3}^{4} ) {}^{3} = \\ {3}^{6} \times {3}^{6} \div {3}^{12} = \\ {3}^{12} \div {3}^{12} = {3}^{0} = 1 \\ \\ {25}^{72} \div {125}^{48} = \\ ( {5}^{2} ) {}^{72} \div ( {5}^{3} ) {}^{48} = \\ {5}^{144} \div {5}^{144 } = {5}^{0} = 1 \\ \\ {2}^{9} \times {3}^{9} = \\ (2 \times 3) {}^{9} = {6}^{9 } \\ \\ {2}^{10} \times {5}^{10} \times {3}^{10} = \\ (2 \times 5 \times 10) {}^{10} = \\ (10 \times 10) {}^{10} = {100}^{10} [/tex]

sper că te-am ajutat!!!