Răspuns :
3
Explicație pas cu pas :
[3 ^48:3^18+(2^4)^5 +6^23:6^13]:[(3^5)^2 ×(2^2) ^5 +3^17×3^13+(2^5)^4]=
[3^(48-18)+2^(4×5) +6 ^(23-13)]:[3 ^(5×2) ×2^(2×5)+3 ^(17+13)+2^(5×4)] =
(3 ^30+2^20+6^10):(3^10×2^10+3^30+2^20)=
(3^30+2^20+6^10):[(3×2) ^10+3^30+2^20]=
(3^30+2^20+6^10):(6^10+3^30+2^20)=
3^30:3^30+2^20:2^20+6^10:6^10=
3^(30-30)+2^(20-20)+6^(10-10)=
3 ^0+2^0+6^0=
1 +1 +1 =
3
#copaceibrainly
