1.
notma monoalcoolul = CnH2n+1OH
30 g 5,6 L
CnH2n+1OH + Na --> CnH2n+1ONa + 1/2H2
miu 22,4x1/2
=> miu = 30x22,4x0,5/5,6 = 60 g/mol
=> 14n+18 = 60 => n = 3 => C3H7OH
CH3-CH2-CH2-OH
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2.
1-a, e
2-a
3-a
4-a, b, d
3.
1-lichida, mici,
2-legaturilor de hidrogen
3-scade , creste
4-volatil, arzator
4.
CH3CH2OH + 3[O] --> CH3COOH + H2O
K2Cr2O7 + 4H2SO4 --> K2SO4 + Cr2(SO4)3 + 4H2O + 3[O]
--------------------------------------------------------------------------------------------
CH3CH2OH+K2Cr2O7+4H2SO4-->CH3COOH+K2SO4+Cr2(SO4)3+5H2O
portocaliu verde
5.
CaC2 + 2H2O --> C2H2 + Ca(OH)2
HC≡CH + H2O --> CH3CH=O
CH3CH=O + H2 --Zn/HCl--> CH3CH2OH
6.
CH3CH2OH O2 --fermentatie aceticum--> CH3COOH + H2O
7.
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8.
4,14 kg m kg
C6H12O6 --fermentatie alcoolica--> 2C2H5OH + 2CO2
180 2x46
=> m = 4,14x2x46/180 = 2,12 kg etanol = 2120 g etanol
nr.moli = n = m/M, M.C2H5OH = 46 g/mol
=> n = 2120/46 = 46 moli
9.
ms = 600g, c% = 40%
din c% => md = msxc%/100
= 600x40/100 = 240 g formaldehida
m g 240 g
CH3OH + [O] --> CH2=O + H2O
32 30
=> m = 32x240/30 = 256 g metanol
