Răspuns:
1.- 90°
2-180°
3-90°-23°=67°
4-360°
5- 20°
6-AOB si BOC=ad. complementare=masura de 90°
AOB= 90°÷2=45°
BOC=45°
DOE=45°÷2=22,5° ; 22,5°×2=45°
7-
a) AOB= |----------|+25|
BOC=2×|----------|+80|
AOC=3×|----------|+45|
25+80+45=150°
AOB+BOC+AOC=360°
360°-150°=210°
210°÷6 segmente=35° ; X=35°
AOB=60°
BOC=150°
AOC=150°
rezolvarea punctului b se afla in poză.
