Răspuns:
A={x€N|2x+4 <=12
x€N => x€{0,1,2,3.......}
2x + 4 <= 12
2x <= 12 - 4
2x <= 8
x<= 8 : 2
x<= 4
x = {0,1,2,3,4}
A={0,1,2,3,4}
B={y€N | 2/3(2 la puterea a treia)<3/x(3 la puterea x )<2
x€N => x€ {0,1,2,3,4........}
2/3 = 6<3/x <2
3/x €{3/0} => x ={1}
B ={1}
