Răspuns :

Miky93id
A=c1*c2 /2=18
c1*c2=36
c1=c2
c1*c1=36
(c1)²=36
c1=6
ΔABC, mas<A=90⇒ TP
BC²=AB²+AC²=6²+6²=36+36=72  ⇒BC=6√2
P=6+6+6√2=12+6√2
Kataraid
p=2l+2L
p=18+18
p=36(perimetrul dreptunghiului isocial.

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