Răspuns:
a) 3(x-1) [tex]\leq[/tex] 5 (x+3) = 3x - 3 [tex]\leq[/tex] 5 + 15 = 3x - 5x [tex]\leq[/tex] 15 + 3 = -2x [tex]\leq[/tex] 18 = x [tex]\geq[/tex] -9
b) 7x - 4(3 + 2x) > x = -x -12 > x = -x -x > 12 = -2x>12 = x < -6
Explicație pas cu pas:
a)
3x-3<<5x+15
-2x>>18
x>>-9
x apartine [-9 , + infinit)
b)
7x-12-8x>x
-x-12>x
-12>2x
x<-6
x apartine (- infinit, -6)
