a) x=6·C+4|+2⇒x+2=6C1+6⇒x+2=6(C1+1)⇒x+2M6
x=18·C+6|+2⇒x+2=18C1+18⇒x+2=18(C1)⇒x+2M18
x=24·C+22|+2⇒x+2=24C1+24⇒x+2=24(C1)⇒x+2M24
[6,18,24]=432
x+2=432⇒x=430
b)a÷6=C1r5
a÷18=C2r5
a÷24=C3r5
APLICAM TIR
d=c·i+r,rmai mic decat i
a=C1·6+5
a=C2·18+5
a=C3·24+5
din a-5=C1·6 si din a-5=C2·18⇒a-5 M comun al nr 6 si 18
6=2·3
18=6·3
[6,18]=18·3=54⇒a-5M54
a-5∈{0,54,100,162,216,270,324...}
a∈{5,24,48,72,96,120,270,324...}
5÷24=0r4...
120÷24=5
2880÷24=120
Sper ca te-am ajutat!!!! ;)
