Răspuns :

b) transpusa C este ca matricea C doar ca randurile devin coloane

deci tC = [tex]\left[\begin{array}{ccc}2&0&1\\1&2&1\\\end{array}\right][/tex]

A- B - tC = [tex]\left[\begin{array}{ccc}1&2&3\\-1&-2&-3\\\end{array}\right] + \left[\begin{array}{ccc}0&1&0\\-1&0&-1\\\end{array}\right] + \left[\begin{array}{ccc}-2&0&-1\\-1&-2&-1\\\end{array}\right] = \left[\begin{array}{ccc}-1&3&2\\-3&-4&-5\\\end{array}\right][/tex]

c) Transpusa A  = [tex]\left[\begin{array}{ccc}1&-1\\2&-2\\3&-3\end{array}\right][/tex]

C-2tA = [tex]\left[\begin{array}{ccc}2&1\\0&2\\1&1\end{array}\right] - \left[\begin{array}{ccc}2&-2\\4&-4\\6&-6\end{array}\right] = \left[\begin{array}{ccc}0&3\\-4&6\\-5&7\end{array}\right][/tex]