Răspuns:
1.m(AOB)=m(DOC)=35°
m(AOD)=m(BOC)=180°-35°=145°
2.m(AOD)=m(BOC)=100°
m(AOB)=m(DOC)=180°-100°=80°
3.m(BOC)+m(COD)=180 =>
=>2x+x=180 =>3x=180 =>x=60°
x=m(DOC)=m(AOB)=60°
2x=m(AOD)=m(BOC)=120°
4.m(AOD)+m(DOC)=180° =>
=>3x+20+x=180° =>4x=180°-20 =>
=>4x=160° =>x= 40°
x=m(DOC)=m(AOB)=40°
3x+20=m(AOD)=m(BOC)=120°+20=140°
