Răspuns :
a) 4sin 30°+6cos 60°+5tg 45°=
=4×1/2+6×1/2+5×1=
=2+3+5=10
b) 2sin 60°-4cos 30°+3tg 60°=
=2×√3/2-4×√3/2+3√3=
=√3-2√3+3√3=2√3
a) 4sin 30°+6cos 60°+5tg 45°=
=4×1/2+6×1/2+5×1=
=2+3+5=10
b) 2sin 60°-4cos 30°+3tg 60°=
=2×√3/2-4×√3/2+3√3=
=√3-2√3+3√3=2√3