1.
verificam formula procentuala sa fie 100%
notam compusul CaHbNc
=> 117g comp. .......12a g C ........... b g H ....... 14c g N
100% comp. ....... 82% ................. 6% ............ 12%
=> a = 8 b = 7 c = 1
=> C8H7N
2.
C6H6
N.E. = (2x6+2-6)/2 = 4
C5H12
N.E. = (2x5+2-12)/2 = 0
C10H8
N.E. = (2x10+2-8)/2 =
C2H2
N.E. = (2x2+2-2)/2 = 2
C8H7N
N.E. = (2x8+2-7+1)/2 = 6
3.
p t t s t p
CH3-CH=CH-CH2-CH-CH3
s CH2
s CH2
t CH=CH2
s