Răspuns :

Lucaselaid

(a+1)² + (b-2)² + (c-3)²= 25

=> 0 ≤ (a+1)² ≤ 25    /√

|a+1| ≤ 5

=> -5 ≤ a+1≤ 5    / -1

-6 ≤ a ≤ 4

=> a ∈ [-6;4]

=> 0 ≤ (b-2)² ≤ 25    /√

|b-2| ≤ 5    

=> -5 ≤ b-2 ≤ 5     /+2

-3≤ b ≤ 7

=>b ∈ [-3;7]

=>0 ≤ (c-3)² ≤ 25   /√

|c-3| ≤ 5

=> -5 ≤ c-3 ≤ 5    /+3

-2≤ c ≤ 8

=> c ∈ [-2;8]