[tex]\it 7)\ A+B+C+D+360^o\\ \\ \{A,\ B,\ C,\ D\}\ d.\ p.\ \{1,\ 2,\ 3,\ 4\} \Rightarrow \dfrac{A}{1}= \dfrac{B}{2}= \dfrac{C}{3}= \dfrac{D}{4} = \dfrac{A+B+C+D}{1+2+3+4} =\\ \\ \\ = \dfrac{360^o}{10}=36^o \Rightarrow \begin{cases} \it A=1\cdot36^o=36^o\\ \\ \it B=2\cdot36^o=72^o\\ \\ \it C=3\cdot36^o=108^o\\ \\ \it D=4\cdot36^o=144^o\end{cases}[/tex]
