Răspuns :
[tex]\it \sqrt[5]{\it x^3}=x^{\frac{3}{5}}\\ \\ F(x)=\int x^{\frac{3}{5}} dx=\dfrac{x^{\frac{3}{5}+1}}{\dfrac{3}{5}+1}+\mathcal{C}= \dfrac{x^{\frac{8}{5}}}{\dfrac{8}{5}}+\mathcal{C}=\dfrac{5}{8}x^{\frac{8}{5}}+\mathcal{C}[/tex]
[tex]\it \sqrt[5]{\it x^3}=x^{\frac{3}{5}}\\ \\ F(x)=\int x^{\frac{3}{5}} dx=\dfrac{x^{\frac{3}{5}+1}}{\dfrac{3}{5}+1}+\mathcal{C}= \dfrac{x^{\frac{8}{5}}}{\dfrac{8}{5}}+\mathcal{C}=\dfrac{5}{8}x^{\frac{8}{5}}+\mathcal{C}[/tex]