Răspuns:
din sol1 si sol2 rezulta sol3
ms3= ms1+ms2
md3= md1+md2
ms3= roxV=1,12g/cm³x6000cm³=6720g
c3= md3x100/ms3---> md3= 50x6720/100g=3360gKOH
md1= c1xms1/100 md2= c2xms2/100
md1+md2=c1xms1/100+c2xms2/100
3360= 0,28ms1+0,56ms2
6720=ms1+ms2
rezolvand sistemul, rezulta ms1=1440g si ms2= 5280g
m,KOH=3360g
M,KOH=56g/mol
M,HCl= 36,5g/mol
56g.......36,5g
KOH + HCl-----> KCl +H2O
3360g.......x
x=m= 60x36,5gHCl= md
c= mdx100/ms---> ms= mdx100/c=60x36,5x100/36,5g=6000gsolHCl
Explicație: