[tex]\it k)\ \dfrac{1}{7}+\Big(-\dfrac{4}{3} \Big)+\dfrac{6}{7} +\dfrac{1}{3} =\dfrac{1}{7}+\dfrac{6}{7}+\dfrac{1}{3} -\dfrac{4}{3} =\dfrac{7}{7}-\dfrac{3}{3}=1-1=0[/tex]
[tex]\it \ell)\ \dfrac{\ \ 100^{(100}}{200} +\dfrac{\ \ 101^{(101}}{303} +\dfrac{\ \ 50^{(50}}{300}=\dfrac{1}{2}+ \dfrac{1}{3}+ \dfrac{1}{6} =1[/tex]
