Salutare!
[tex]\bf 2^{30}:2^{25}+2^{4^{0}}-2\cdot [128:2^{5}+2^{3} :(2\cdot 2^{4}-24)]=[/tex]
[tex]\bf 2^{30-25}+2^{1}-2\cdot [2^{7}:2^{5}+2^{3} :(2^{1+4}-24)]=[/tex]
[tex]\bf 2^{5}+2-2\cdot [2^{7-5}+2^{3} :(2^{5}-24)]=[/tex]
[tex]\bf 2^{5}+2-2\cdot [2^{2}+2^{3} :(32-24)]=[/tex]
[tex]\bf 2^{5}+2-2\cdot (2^{2}+2^{3} :8)=[/tex]
[tex]\bf 2^{5}+2-2\cdot (2^{2}+2^{3} :2^{3})=[/tex]
[tex]\bf 2^{5}+2-2\cdot (2^{2}+2^{3-3})=[/tex]
[tex]\bf 2^{5}+2-2\cdot (4+2^{0})=[/tex]
[tex]\bf 2^{5}+2-2\cdot (4+1)=[/tex]
[tex]\bf 2^{5}+2-2\cdot 5=[/tex]
[tex]\bf 32+2-10=[/tex]
[tex]\boxed{\bf 24}[/tex]
[tex]\bf 2^{4^{0}} = 2^{1} = 2[/tex]
Cateva formule pentru puteri
a⁰ = 1 sau 1 = a⁰
(aⁿ)ᵇ = aⁿ ˣ ᵇ sau aⁿ ˣ ᵇ = (aⁿ) ᵇ
aⁿ · aᵇ = (a · a) ⁿ ⁺ ᵇ sau (a · a) ⁿ ⁺ ᵇ = aⁿ · aᵇ
aⁿ : aᵇ = (a : a) ⁿ ⁻ ᵇ sau (a : a) ⁿ ⁻ ᵇ = aⁿ : aᵇ
aⁿ · bⁿ = (a · b)ⁿ sau (a · b)ⁿ = aⁿ · bⁿ
aⁿ : bⁿ = (a : b)ⁿ sau (a : b)ⁿ = aⁿ : bⁿ
