Răspuns:
m C= 417 kg = m T
η= 45%
p CH₄= 87%
9x/20 y 417 kg
CH₄ + O₂ -> C + 2H₂O
22,4 22,4 12 kg
η=( m P/ m T )*100 => m P= m T*η/100 - in cazul nostru, rap, la volumul de CH₄ notat cu x.
V P= 45x/100= 9x/20
9x/20= 22,4*417/12=> 9x*12= 20*22,4*417 => 108x= 186816 => x=1729,78 L CH₄ pur
care se form din imp.
p= (V CH₄ pur./ V CH₄ imp)*100 => V CH₄ imp= V CH₄ pur*100/p
V CH₄ imp= 1729,78*100,87= 1988,25 m³ CH₄
y= 417*22,4/12 = 778,4 m³ O₂
V aer= 5 * V O₂= 5*778,4= 3892 m³ aer
