Răspuns:
Explicație pas cu pas:
[tex]a=(-\dfrac{^{8)}1}{2}+\dfrac{^{4)}1}{4}-\dfrac{^{2)}1}{8}+\dfrac{1}{16}):(-\dfrac{^{27)}1}{3}+\dfrac{^{9)}1}{9}-\dfrac{^{3)}1}{27}+\dfrac{1}{81})=\\=(-\dfrac{8}{16}+\dfrac{4}{16}-\dfrac{2}{16}+\dfrac{1}{16}):(-\dfrac{27}{81}+\dfrac{9}{81}-\dfrac{3}{81}+ \dfrac{1}{81})=\\=\dfrac{-8+4-2+1}{16}:\dfrac{-27+9-3+1}{81}=\dfrac{-5}{16}:\dfrac{-20}{81}=\dfrac{-5}{16} *\dfrac{81}{-20}=\dfrac{81}{64}>0.[/tex]