Răspuns :

a)

[tex]\bf \dfrac{x^{2}-9}{x^{2} -3x}= \dfrac{x^{2}-3^{2}}{x\cdot(x -3)}= \dfrac{(x +3)\cdot(x -3)}{x\cdot(x -3)}=\dfrac{(x +3)}{x}[/tex]

b)

[tex]\bf \dfrac{x^{2}-36}{x^{2} -12x+36}= \dfrac{x^{2}-6^{2}}{(x -6)^{2}}= \dfrac{(x +6)\cdot(x -6)}{(x -6)^{2}}=\dfrac{x +6}{x-6}[/tex]

Dly23id

[tex] \frac{ {x}^{2} - 9 }{ {x}^{2} - 3x } = \frac{(x - 3)(x + 3)}{x(x - 3)} = \frac{x + 3}{x} [/tex]

[tex] \frac{ {x}^{2} - 36}{(x - 6 {)}^{2} } = \frac{(x - 6)(x + 6)}{(x - 6 {)}^{2} } = \frac{x + 6}{x - 6} [/tex]

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