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Rezolva-ti in R ecuatiile:​
a)3(2x-1)-5(3x-1)=1
b)4(x+2)=2(3x-1+5
c)3(y+4)-(-3+y)×(-2)=3
d)6(z+3)-25=5(2z-1)+3z
e)4(t+3)-5(1-2t)=6t-1
f)5(x+2)-18=2(x-5)-x.
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Răspuns :

Ariadnabutucid

a) 3(2x-1)-5(3x-1)=1

6x-3-15x+5=1

-9x+2=1

-9x=1-2

-9x=-1

S={ 1/9 }

b)4(x+2)=2(3x-1+5)

4x+8=2(3x+4)

4x+8=6x+8

4x=6x

4x-6x=0

-2x=0

S = {0}

c) 3(y+4)-(-3+y)×(-2)=3

3y+12+(-3+y)×2=3

3y+12-6+2y=3

5y+6=3

5y=3-6

5y=-3

S={y=-3/5}

d)6(z+3)-25=5(2z-1)+3z

6z+18-25=10z-5+3z

6z-7=13z-5

6z-13z=-5+7

-7z=2

S={z=-2/7}

e)4(t+3)-5(1-2t)=6t-1

4t+12-5+10t=6t-1

14t+7=6t-1

14t-6t=-1-7

8t=-8

S={t=-1}

f)5(x+2)-18=2(x-5)-x

5x+10-18=2x-12x-10-x

5x-8=x-10

5x-x=-10+8

4x=-2

S={x=-1/2}