Răspuns :

HawkEyedid

Răspuns:

1)

3(2x-1)+7=5(x-1)+7

6x - 3 + 7 = 5x - 5 + 7

6x + 4 = 5x + 2

6x - 5x = 2 - 4

x = -2

2)

3(2x-1)+6x=10x-7

6x - 3 + 6x = 10x - 7

12x - 3 = 10x - 7

12x - 10x = - 7 + 3

2x = - 4

x = -4 : 2

x = - 2

1)

[tex]\bf 3\cdot(2x-1)+7=5\cdot(x-1)+7[/tex]

[tex]\bf 6x - 3 + 7 = 5x - 5 + 7[/tex]

[tex]\bf 6x + 4 = 5x + 2[/tex]

[tex]\bf 6x = 5x + 2 -4[/tex]

[tex]\bf 6x = 5x -2[/tex]

[tex]\bf 6x -5x =-2[/tex]

[tex]\boxed{\bf x = -2}[/tex]  ∈ IR

2)

[tex]\bf 3\cdot(2x-1)+6x=10x-7[/tex]

[tex]\bf 6x-3+6x=10x-7[/tex]

[tex]\bf 12x-3=10x-7[/tex]

[tex]\bf 12x=10x-7 +3[/tex]

[tex]\bf 12x=10x-4[/tex]

[tex]\bf 12x-10x=-4[/tex]

[tex]\bf 2x= -4\:\:|:2\:\:\text{\it impartim toata relatia cu 2}[/tex]

[tex]\boxed{\bf x = -2}[/tex]  ∈ IR

ID Alte intrebari