Răspuns:
Explicație pas cu pas:
[tex]-\sqrt{\dfrac{2}{7} }* \sqrt{3\dfrac{1}{2} }=-\sqrt{\dfrac{2}{7} }*\sqrt{\dfrac{3*2+1}{2} }=-\sqrt{\dfrac{2}{7} }*\sqrt{\dfrac{7}{2} }=-\sqrt{\dfrac{2}{7}*\dfrac{7}{2} }=-\sqrt{1}=-1.\\-338:\sqrt{98} =-\dfrac{338}{\sqrt{49*2} }=-\dfrac{338}{7\sqrt{2} }=-\dfrac{338\sqrt{2} }{7*(\sqrt{2})^2 }=-\dfrac{338\sqrt{2} }{7*2}=-\dfrac{169\sqrt{2} }{7}.\\\sqrt{\dfrac{5,4}{9,4}}= \sqrt{\dfrac{54}{94}}=\sqrt{\dfrac{27}{49} }=\dfrac{\sqrt{27} }{\sqrt{49} }=\dfrac{\sqrt{9*3} }{7}=\dfrac{3\sqrt{3} }{7}.[/tex]