Răspuns :
[tex]\bf \dfrac{x-2}{(-1)^{2}+3\cdot(-2)} =\dfrac{(-5+7)\cdot(-2)^2}{(-2)^{3}}[/tex]
[tex]\bf \dfrac{x-2}{1-6} =\dfrac{(2)\cdot2^2}{-8}}[/tex]
[tex]\bf \dfrac{x-2}{-5} =\dfrac{2^{3}}{-8}}[/tex]
[tex]\bf \dfrac{x-2}{-5} =-\dfrac{2^{3}}{2^{3}}[/tex]
[tex]\bf \dfrac{x-2}{-5} =-\dfrac{\not2^{3}}{\not2^{3}}[/tex]
[tex]\bf \dfrac{x-2}{-5} =-1[/tex]
[tex]\bf x-2 =-1\cdot(-5)[/tex]
[tex]\bf x-2 =5[/tex]
[tex]\bf x =5+2[/tex]
[tex]\boxed{\bf x=7}[/tex] ∈ Ζ
[tex]\frac{x-2}{(-1)^2+3*(-2)} =\frac{(-5+7)*(-2)^2}{(-2)^3} \\\\\frac{x-2}{1-6} =\frac{2*4}{-8}\\\\\frac{x-2}{-5}=\frac{8}{-8} \\\\\frac{x-2}{-5}=-1\\\\x-2=-1*( -5)\\\\x-2=5\\\\x=5+2[/tex]
⇒x=7 , 7∈Z (A)