Baftă!! ✪ ω ✪
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b)
[tex]\\[/tex]{2(x+1)-3(y-1)=-1 {x=-3+[tex]\frac{3}{2}[/tex]*y {5(x-2)-4(y-3)=1⇒{5(x-2)-4(y-3)=1⇒ y=4⇒x=-3+[tex]\frac{3}{2}\\[/tex]*4⇒x=3
d)
{2(x+y)+3(y-x)=33 {x=-33+5y {3(2x+y)+4(x-y)=-36⇒{3(2x+y)+4(x-y)=-36⇒y=6⇒x=-33+5*6⇒x=-3
