Fie a si b cele doua nr
[tex]a=\frac{4b}{5}[/tex]
a-b=16
[tex]\frac{4b}{5} -b=16\\\\\frac{4b}{5}- \frac{5b}{5} =\frac{80}{5} |*5\\\\4b-5b=80\\\\-b=80=>b= -80[/tex]
a-b=16
a-(-80)=16
a+80=16
a=16-80
a= -64
Verificare: a-b=16
-64-(-80)=16
-64+80=16
16=16 (A)