[tex]\it a)\ 3^5\cdot(3^7+3^9)=3^5\cdot3^7+3^5\cdot3^9=3^{5+7}+3^{5+9}=3^{12}+3^{14}\\ \\ b)\ 6^{10}\cdot(6^{10}-6)=6^{10}\cdot6^{10}-6^{10}\cdot6=6^{10+10}-6^{10+1}=6^{20}-6^{11}\\ \\ c)\ 7^4\cdot(7^8+1)=7^4\cdot7^8+7^4\cdot1=7^{12}+7^4[/tex]
Răspuns:
Explicație pas cu pas:
a)
3⁵*3⁷+3⁵*3⁹
-
b)
6¹⁰*6¹⁰-6¹⁰*6
c)
7⁴*7⁸+7⁴*1
