Răspuns:
a>b
Explicație pas cu pas:
[tex]a=\dfrac{6\sqrt{3}}{\sqrt{2}}= \dfrac{6\sqrt{3}*\sqrt{2} }{(\sqrt{2})^2}=\dfrac{6\sqrt{6} }{2}=3\sqrt{6}\\b=5\sqrt{2} \\Fie a<b,~ =>~3\sqrt{6}<5\sqrt{2}~|^2,~~=>~(3\sqrt{6})^2<(5\sqrt{2})^2,~=>~3^2*(\sqrt{6})^2<5^2*(\sqrt{2})^2,~=>~9*6<25*2,~=>~54<50, fals, ~=>~a>b.[/tex]
