Răspuns :
-3≤(x+1)/2≤1 /×2
-6≤x+1≤2 /-1
-7≤x≤1
x∈{-7,-6,-5,-4,-3,-2,-1,0,1}
-3 ≤ (x + 1/)2 ≤ 1 |•2
-6 ≤ x + 1 ≤ 2 |-1
-7 ≤ x ≤ 1
x € {-7, -6, -5, -4, -3, -2, -1, 0, 1}
-3≤(x+1)/2≤1 /×2
-6≤x+1≤2 /-1
-7≤x≤1
x∈{-7,-6,-5,-4,-3,-2,-1,0,1}
-3 ≤ (x + 1/)2 ≤ 1 |•2
-6 ≤ x + 1 ≤ 2 |-1
-7 ≤ x ≤ 1
x € {-7, -6, -5, -4, -3, -2, -1, 0, 1}