Este ecuația de la ex 2 , se poate vedea in poza

[tex]\frac{x}{3} -\frac{4-x}{2} =8\frac{5}{6} -\frac{x}{4} <=>^{4)} \frac{x}{3} -^{6)} \frac{4-x}{2} =^{2)} \frac{53}{6} -^{3)} \frac{x}{4} <=> 4x-6(4-x)=106-3x <=> 4x-24+6x=106-3x <=> 10x+3x=106+24 <=> 13x=130 => x=10[/tex]

[tex]8\frac{6}{5} =\frac{8*6+5}{6} =\frac{53}{6}[/tex]

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Pav38id Pav38id · Answer 2

[tex]\it \dfrac{x}{3}-\dfrac{4-x}{2} =\dfrac{8\cdot6+5}{6}-\dfrac{x}{4}[/tex]

[tex]\it \dfrac{x\cdot2}{6}-\dfrac{3\cdot4-3\cdot x}{6} =\dfrac{48+5}{6}-\dfrac{x}{4}[/tex]

[tex]\it \dfrac{2x-12+3x}{6}} =\dfrac{53}{6}-\dfrac{x}{4}[/tex]

[tex]\it \dfrac{5x-12}{6}} =\dfrac{53\cdot2}{12}-\dfrac{x\cdot3}{12}[/tex]

[tex]\it \dfrac{5x-12}{6}} =\dfrac{106-3x}{12}}[/tex]

[tex]\it 12\cdot(5x-12)=6\cdot(106-3x)\:\:\:|:6[/tex]

[tex]\it 2\cdot5x-2\cdot12=106-3x[/tex]

[tex]\it 10x-24=106-3x[/tex]

[tex]\it 13x = 130[/tex]

[tex]\it \boxed{\it x = 10}[/tex]

꧁ Mult succes în continuare ! ꧂