Răspuns :

Aledan12id

Salut!

x/y=2/3 ⇔ 3x=2y ⇔ x=2y/3

2x/(2x+5y)=

(2·2y/3)/(2·2y/3 + 5y)=

(4y/3)/(4y/3 + 15y/3)=

(4y/3)/(19y/3)=

4y/3 · 3/19y=

3 si y se simplifica si iasa asa

=4/19

Succes!

Rayzenid

[tex]\dfrac{x}{y} = \dfrac{2}{3}[/tex]

[tex]{\dfrac{2x}{2x+5y}}^{^{\displaystyle (y}} = \dfrac{2\cdot \frac{x}{y}}{2\cdot \frac{x}{y}+5} =\!{^{^{^{^{^{^{\displaystyle 3)}}}}}}}\!\!\dfrac{2\cdot \frac{2}{3}}{2\cdot \frac{2}{3}+5} = \dfrac{2\cdot 2}{2\cdot 2+3\cdot 5} = \dfrac{4}{19}[/tex]

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