Răspuns:
[tex] \frac{16}{2 - \sqrt{3} } + \frac{12}{ \sqrt{3} + 1 } - \frac{6}{2 \sqrt{3} - 3 } - \frac{8}{3 \sqrt{3} + 5 } = 16(2 + \sqrt{3)} + 6( \sqrt{3} - 1) - 2(2 \sqrt{3} + 3) - 4(3 \sqrt{3} - 5) = 32 + 16 \sqrt{3} + 6 \sqrt{3} - 6 - 4 \sqrt{3} - 6 - 12 \sqrt{3} + 20 = 40 + 6 \sqrt{3} [/tex]
Sper ca te-am ajutat :)
