Răspuns:
Explicație pas cu pas:
A(0,2), B(1,-1), C(3,4). Fie G centru de greutate, atunci
[tex]x_G=\dfrac{x_A+x_B+x_C}{3}=\dfrac{0+1+3}{3}=\dfrac{4}{3}\\y_G=\dfrac{y_A+y_B+y_C}{3}=\dfrac{2+(-1)+4}{3}=\dfrac{5}{3}\\Deci,~~G(\dfrac{4}{3},~\dfrac{5}{3})[/tex]
