Răspuns:
Explicație pas cu pas:
a)
Ix - 2I - 11 = -2Ix - 2I + 4
Ix - 2I + 2Ix - 2I = 11 + 4
3Ix - 2I = 15
Ix - 2I = 5
x - 2 = -5; 5
x = -3; 7
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b)
-2Ix + 3I + 4Ix + 3I = 15 - 5Ix + 3I - 1
-2Ix + 3I + 4Ix + 3I + 5Ix + 3I = 15 - 1
7Ix + 3I = 14
Ix + 3I = 2
x + 3 = -2; 2
x = -5; -1
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c)
3Ix + 1I + 5 = Ix + 1I + 11
3Ix + 1I - Ix + 1I = 11 - 5
2Ix + 1I = 6
Ix + 1I = 3
x + 1 = -3; 3
x = -4; 2
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d)
-4I2x - 1I + 2 = -2I2x - 1I - 7
4I2x - 1I - 2I2x - 1I = 7 + 2
2I2x - 1I = 9
I2x - 1I = 9/2
2x - 1 = -9/2; 9/2
2x = -7/2; 11/2
x = -7/4; 11/4
nu are solutii in multimea numerelor intregi
