[tex]\bf \Big\{ \big[(2a-3 \big)\cdot 2-2^{2}\big]: 5+103^{0}\Big\}\cdot3-1^{2018} = 8[/tex]
[tex]\bf \Big\{ \big[\big(2a-3\big)\cdot 2 - 4\big]:5+1 \Big\}\cdot 3-1 = 8[/tex]
[tex]\bf \Big[\big(4a-6- 4\big):5+1\Big]\cdot3 = 8+1[/tex]
[tex]\bf \Big[ \big(4a-10\big):5+1\Big]\cdot3 = 9~~~\bigg|:3[/tex]
[tex]\bf \big(4a-10\big):5+1 = 3[/tex]
[tex]\bf \big(4a-10\big):5 = 3-1~~~\bigg|\cdot5[/tex]
[tex]\bf 4a-10= 2 \cdot 5[/tex]
[tex]\bf 4a= 10+10[/tex]
[tex]\bf 4a=20~~~\bigg|:4[/tex]
[tex]\large \red{\boxed{\bf a=5}}[/tex]
Câteva formule pentru puteri:
a⁰ = 1 sau 1 = a⁰
(- a)ⁿ, unde n este o putere para (-a)ⁿ = aⁿ
aⁿ · aᵇ = (a · a) ⁿ ⁺ ᵇ sau (a · a) ⁿ ⁺ ᵇ = aⁿ · aᵇ
aⁿ : aᵇ = (a : a) ⁿ ⁻ ᵇ sau (a : a) ⁿ ⁻ ᵇ = aⁿ : aᵇ
aⁿ · bⁿ = (a · b)ⁿ sau (a · b)ⁿ = aⁿ · bⁿ
aⁿ : bⁿ = (a : b)ⁿ sau (a : b)ⁿ = aⁿ : bⁿ
(aⁿ)ᵇ = aⁿ ˣ ᵇ sau aⁿ ˣ ᵇ = (aⁿ) ᵇ
Bafta multa !
