Răspuns :

Răspuns:

Explicație pas cu pas:

l = 2√3 dm

P = 3l = 3*2√3 = 6√3 dm

A = l^2*√3/4 = 12√3/4 = 3√3 dm^2

Targoviste44id

[tex]\it \mathcal{P}=3\cdot \ell = 3\cdot2\sqrt3=6\sqrt3\ dm\\ \\ \\ \mathcal{A}=\dfrac{\ell^2\sqrt3}{4}=\dfrac{(2\sqrt3)^2\sqrt3}{4}=\dfrac{2\sqrt3\cdot2\sqrt3\cdot\sqrt3}{4}=\dfrac{\ \ 4\cdot3\sqrt3\ ^{(4}}{4}=3\sqrt3\ dm^2[/tex]

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