Răspuns:
Explicație pas cu pas:
CE⊥AB
In Δ CEB EB²=BC²-AD²=16×3-16×2=16 EB=4cm
In ΔACB teorema inaltimii
a)CE²=AE×EB 16×2=AE×4 AE=8cm
AB=AE+EB=8+4=12 cm
CD=AE=8 cm
b)
AC²=AE×AB=8×12=2³×2²×3 AC=4√6 cm
BD²=AD²+AB²=16×2+144=176 BD=4√11 cm
c) DF⊥AC
in ΔADC AD×CD=DF×AC 4√2×8=4√6×DF
DF=8:√3=8√3/3
